How many grams will dissolve on 3.0*10^2mL of 0.050 M Ca(NO3)2? Ksp=8.7*10^-9

Your question makes no sense to me. How many grams of WHAT will dissolve in 0.05 M Ca(NO3)2?

To determine the number of grams that will dissolve in a given volume of solution, we need to use the solubility product constant (Ksp) value.

The solubility product constant (Ksp) is the equilibrium constant for the dissolution of an ionic compound in a solution. It represents the product of the concentrations of the dissolved ions raised to their stoichiometric coefficients.

In this case, the compound is Ca(NO3)2, and its formula indicates that it dissolves to produce one Ca2+ ion and two NO3- ions. Therefore, the equation for its dissolution is:

Ca(NO3)2(s) ⟺ Ca2+(aq) + 2NO3-(aq)

The Ksp value given is 8.7*10^-9.

To find the number of grams that will dissolve, we need to use the stoichiometry of the balanced equation to relate the concentration of the ions to the amount of the compound.

First, we need to calculate the concentration of the ions in the solution.

Given:
Volume of solution = 3.0*10^2 mL = 300 mL = 0.300 L
Molarity = 0.050 M

The concentration of Ca2+ ions is simply equal to the molarity of the solution:
[Ca2+] = 0.050 M

The concentration of NO3- ions is twice the molarity of the solution since two NO3- ions are produced per one Ca(NO3)2 molecule:
[NO3-] = 2 * (0.050 M) = 0.100 M

Now that we have calculated the concentrations of the ions, we can use them to find the solubility of the compound by rearranging the equilibrium expression for Ksp:

Ksp = [Ca2+][NO3-]^2

Substituting the values we found:

8.7*10^-9 = (0.050 M)(0.100 M)^2

Simplifying, we get:

8.7*10^-9 = 0.05 * 0.01 * 0.01

To solve for the number of grams that will dissolve, we need to rearrange the equation to isolate the mass:

mass = (Ksp / ([Ca2+][NO3-]^2))

Substituting the values:

mass = (8.7*10^-9) / (0.05 * 0.01 * 0.01)

Calculating this, we get:

mass = 0.174 g

Therefore, approximately 0.174 grams of Ca(NO3)2 will dissolve in 300 mL of 0.050 M Ca(NO3)2 solution, given a Ksp value of 8.7*10^-9.