Suppose Kalvin flipped a coin to determine his breakfast cereal every day starting on his 12th birthday and continuing until his 18th birthday. How many times would you expect him to eat Cocoablast cereal.

I know 6 years times 365 days is 2190 what do I do next

did they say how many types of cereal there were?

No I am taking it is two

Would it be half of 2190?

To calculate the number of times Kalvin would expect to eat Cocoablast cereal, we need to determine the probability of him choosing Cocoablast cereal on any given day.

Since he flips a coin, there are two possible outcomes - heads or tails. Let's assume he decides to eat Cocoablast cereal if the coin lands on heads and chooses another cereal if it lands on tails.

Assuming the coin is fair, the probability of getting heads (and eating Cocoablast cereal) is 1/2, and the probability of getting tails (and eating another cereal) is also 1/2.

Now, to find the expected number of times Kalvin would eat Cocoablast cereal, we multiply the probability of choosing Cocoablast cereal on any given day (1/2) by the total number of days over 6 years (2190).

Expected number of times = Probability of choosing Cocoablast cereal * Total number of days

Expected number of times = (1/2) * 2190

Expected number of times = 1095

Therefore, you would expect Kalvin to eat Cocoablast cereal approximately 1095 times during the six-year period.