Physics
posted by Stefan on .
A 2.40 m length of wire is held in an eastwest direction and moves horizontally to the north with a speed of 15.1 m/s. The vertical component of Earth's magnetic field in this region is 40.0 µT directed downward. Calculate the induced emf between the ends of the wire and determine which end is positive.
*I tried using the formula E=Blv where B is the magnetic field (4.0e5 T), but the program says I'm off by a multiple of ten. I'm assuming I'm making a stupid mistake, but I can't figure out what it is!

BLv is correct. 40E6*2.40*15.1=1.45mVolts I get.