algebra
posted by Laura on .
don't quite understand how to go about finding the answer to this problem. I have to find two different points for a line, graph it, and also above or below the line to show the relationship. How do I go about doing this?
The equation is: 3y8x >24
Thank you so much!

Consider the equation 3y  8x = 24
it is easy to find the intercepts, that would give you two points to determine the boundary line
let x=0 , then y = 3 > point (0,8)
let y = 0 , then x = 8 > point (3,0)
joint these two points with a dotted line
shade in the region above the line.
(the original can be changed to
3y > 8x + 24
y > (8/3)x + 8
If y > mx + b, shade the region ABOVE the corresponding line
if y < mx + b , shade the region BELOW the line ) 
log 1
12
evaluate the expression
in not sure how to sove for this