Posted by Kim on Monday, March 21, 2011 at 3:22pm.
Check my thinking on this.
The gas starts as 16.8 kPa Ptotal.
It ends up as 25.2 kPa Ptotal.
Look at the equations.
C2H2 + 5/2 O2 = 2CO2 + H2O
CH4 + 2O2 ==> CO2 + 2H2O
You can see that 1 mol C2H2 produces 2 moles CO2 while 1 mol CH4 produces 1 mol CO2. IF WE HAD 100% CH4, we would expect to obtain 16.8 kPa CO2. The difference (25.2-16.8 = 8.4) must be due to the C2H2 present. Then 16.8 = Ptotal and 8.4 = PC2H2 and 16.8-8.4 = 8.4 PCH4. So we are starting with 8.4 kPa CH4 and 8.4 kPa C2H2 or 50% each.
wrong, answer is that the methane makes up 46% of the gases being burned. (I have the chem textbook that the Q comes from).
wrong, answer is that the methane makes up 46% of the gases being burned. (I have the chem textbook that the Q comes from).
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