The charged plates of a parallel plate capacitor each have a charge density of 3 x 10-3 C/m2. What is the electric field E between the plates?

To find the electric field E between the plates of a parallel plate capacitor, you can use the formula:

E = σ / ε₀

where:
- E is the electric field between the plates,
- σ is the charge density of the plates,
- ε₀ is the permittivity of free space.

In this case, the charge density σ is given as 3 x 10^-3 C/m^2. The permittivity of free space ε₀ is a constant with a value of 8.85 x 10^-12 C^2/(N·m^2).

Now, let's substitute the given values into the formula:

E = (3 x 10^-3 C/m^2) / (8.85 x 10^-12 C^2/(N·m^2))

To simplify the expression, we can perform the division first:

E = (3 x 10^-3) / (8.85 x 10^-12) N/m^2

We can also multiply the numerator and denominator by 10^12 to convert to pico- units:

E = (3 x 10^-3) / (8.85) x 10^9 N/m^2

Now, we can calculate the electric field E:

E ≈ 3.39 x 10^6 N/m^2

Therefore, the electric field between the plates is approximately 3.39 x 10^6 N/m^2.