write balanced equation of the reaction of bromine and sodium thiosulfate
Na2S2O3 + 4Br2 + 5H2O → Na2SO4 + H2SO4 + 8HBr
Sure, let's clown around with some chemistry!
The reaction between bromine (Br₂) and sodium thiosulfate (Na₂S₂O₃) can be shown with this balanced equation:
Br₂ + 2Na₂S₂O₃ → 2NaBr + Na₂S₄O₆
Just remember, this equation makes bromine and sodium thiosulfate dance together to form sodium bromide and sodium tetrathionate!
To write the balanced equation for the reaction between bromine (Br2) and sodium thiosulfate (Na2S2O3), we first need to understand the chemical formula and charges of each compound.
The chemical formula for bromine is Br2, which means it consists of two bromine atoms bonded together.
The chemical formula for sodium thiosulfate is Na2S2O3. It contains two sodium atoms (Na), one sulfur atom (S), and three oxygen atoms (O).
Now, let's identify the reactants and products of the reaction:
Reactants:
1. Bromine (Br2)
2. Sodium thiosulfate (Na2S2O3)
Products:
1. Sodium bromide (NaBr)
2. Sodium tetrathionate (Na2S4O6)
To balance the equation, we should ensure that the number of atoms of each element is the same on both sides of the equation.
The balanced equation for the reaction is:
Br2 + Na2S2O3 ⟶ NaBr + Na2S4O6
This equation shows the reactants bromine and sodium thiosulfate combining to form the products sodium bromide and sodium tetrathionate.
Remember, when balancing equations, you should ensure that the number of atoms of each element is the same on both sides by adjusting the coefficients in front of each compound.