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April 20, 2014

Homework Help: High School Chemistry

Posted by Becky on Monday, March 21, 2011 at 12:58am.

10mL of 0.10M HCl is given. What is the pH? How many milliliters of 0.10M NaOH would be required to neutralize it? What is the pH of the neutralized solution? What would the pH of the solution be if you added 20mL of NaOH?

Here's what I have so far:
pH of HCl=-log(0.10M)= 1

HCl + NaOH --> NaCl + H2O
C1*V1=C2*V2
(0.10M)V1=(0.10M)(0.010L)
V1=0.010L=10mL of 0.10M NaOH

The pH of neutralized solution would be 7 because NaCl is a salt from a strong base and strong acid, and NaCl in water has a neutral pH which is 7.

Thank you in advance!

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