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August 1, 2015

Homework Help: Chemistry

Posted by Cassie on Sunday, March 20, 2011 at 11:23pm.

3.92g of a nondissociating compound are dissolved in 400.g of liquid benzene. The freezing point of the solution is 5.19 degrees celsius. Calculate the molar mass of the compound. (The freezing point of the pure benzene is 5.50 degrees celsius and its molal freezing point depression is 5.12 degrees celsius x kg/mole. (Answer= 1.6 x 10^2 g/mol)

I've been using this equation to solve below but am not getting near the correct answer. Can you please help?

Delta T = Kf mass of solute
--------------------
mole mass solute x kg solvent

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