Friday
April 18, 2014

Homework Help: Chemistry

Posted by Cassie on Sunday, March 20, 2011 at 11:23pm.

3.92g of a nondissociating compound are dissolved in 400.g of liquid benzene. The freezing point of the solution is 5.19 degrees celsius. Calculate the molar mass of the compound. (The freezing point of the pure benzene is 5.50 degrees celsius and its molal freezing point depression is 5.12 degrees celsius x kg/mole. (Answer= 1.6 x 10^2 g/mol)

I've been using this equation to solve below but am not getting near the correct answer. Can you please help?

Delta T = Kf mass of solute
--------------------
mole mass solute x kg solvent

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

chem - a compound containing only boron, nitrogen and hydrogen was found to be ...
Chemistry - When 0.354 g of an unknown nonelectrolyte compound was dissolved in ...
Chemistry - Analysis of a compound indicates that it is 49.02% carbon, 2.743% ...
Chemistry - Analysis of a compound indicates that it is 49.02% carbon, 2.743% ...
Chemistry - Analysis of a compound indicates that it is 49.02% carbon, 2.743% ...
Chemistry - A compound containing only boron, nitrogen, and hydrogen was found ...
chemistry - 2. When 0.354 g of an unknown nonelectrolyte compound was dissolved ...
chemistry - 2. When 0.354 g of an unknown nonelectrolyte compound was dissolved ...
chem- molar weight - I worked this problem, I would like to know if I did it ...
Chemistry - Pure benzene has a normal freezing point of 5.50 degrees Celsius. A...

Search
Members