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September 20, 2014

September 20, 2014

Posted by **Janet** on Sunday, March 20, 2011 at 7:47pm.

Y=xtan(x)

I solved first derivative

xsec^2(x) + tan(x)

I don't understand how to get the first...can someone show me the steps with explanation?

- Calculus -
**Janet**, Sunday, March 20, 2011 at 7:48pmSorry I don't understand how to get the second derivative, I gsolved the first derivative already

- Calculus -
**bobpursley**, Sunday, March 20, 2011 at 8:04pmwell, the derivative of tan(x) is sec^2(x) that part is trivial.

derivative of x(sec^2(x)) is

y=uv

y'=vu' + uv'

let u=x v=sec^2=cos^-2

u'=1 v'=-2cos^-3*(-sin)

v'=2tan(x)sec^2x

so overall, the

f"=2x tan(x)sec^2(x)+sec^2(x)+sec^2(x)

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