Posted by linda on .
find an equation of the curve that passes through the point (1,1) and whose slope at (x,y) is y^2/x^3

calculus 
bobpursley,
dy/dx=y^2/x^3
y^2 dy= x^3 dx
y^1=x^2*1/2 + C
check:take the derivative.
y^2 y'=x^3
dy/dx=y^2/x^3
so find c at by putting 1,1 into the equation
1/y=1/x^2 + C