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March 30, 2015

March 30, 2015

Posted by **linda** on Sunday, March 20, 2011 at 7:18pm.

- calculus -
**bobpursley**, Sunday, March 20, 2011 at 8:10pmdy/dx=y^2/x^3

y^-2 dy= x^-3 dx

-y^-1=-x^-2*1/2 + C

check:take the derivative.

y^-2 y'=x^-3

dy/dx=y^2/x^3

so find c at by putting 1,1 into the equation

1/y=1/x^2 + C

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