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March 25, 2017

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find an equation of the curve that passes through the point (1,1) and whose slope at (x,y) is y^2/x^3

  • calculus - ,

    dy/dx=y^2/x^3

    y^-2 dy= x^-3 dx

    -y^-1=-x^-2*1/2 + C

    check:take the derivative.
    y^-2 y'=x^-3
    dy/dx=y^2/x^3

    so find c at by putting 1,1 into the equation

    1/y=1/x^2 + C

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