Posted by Vanda on Sunday, March 20, 2011 at 4:52pm.
The energy of the photoemission electrons is
E = [ h*c/(wavelength)] - 1.8 V* e
(a) Divide that by electron charge (e) for the stopping potential.
(b) Use E = (1/2)m V^2 to solve for V
Related Questions
Physics - The greater the work function for a metal, A) the greater the speed of...
physics - The greater the work function for a metal, A) the greater the speed of...
Physics - What visible wavelengths will eject electrons from a a metal with a ...
Physics - The "work function", or the minimum energy needed to eject ...
Chemistry - A laser emitting light with a wavelength of 480 nm is directed ...
Gen Chem - Light of wavelength 272 nm shines on a piece of magnesium metal. What...
P-Chem - I am a bit confused on working this problem: Given that the work ...
Physics - Electrons are ejected from a metallic surface with speeds ranging up ...
Chemistry - When light of a wavelength of 125 nm strikes a certain metal, ...
physics - Light falls on a photoelectric surface that has a work function of 2....
For Further Reading