Sunday
April 20, 2014

Homework Help: Physics

Posted by William on Sunday, March 20, 2011 at 4:14pm.

A car moves with a speed v on a horizontal circular highway turn of radius is R = 100. Assume the height of the carís center of mass above the ground is h = 1 m, and the separation between its inner and outer wheels (car's width) is w = 2 m. The car does not skid (static friction works between tires and road surface).
With what maximum speed (in mph) can the car negotiate the turn with without losing equilibrium and starting to overturn? Use g = 10 m/s^2.

Hint 1: car is in circular motion with constant speed. Hint 2: car starts to rotate about its center of gravity when net torque about its center of gravity becomes non-zero. Hint 3: draw an extended free body diagram and identify two torques counteracting each other: torque due to friction force on the inner tire versus torque due to normal force on the outer tire (assume that at the moment the car lifts its inner tires, the normal force becomes equal to the carís weight: N = mg). Hint 4: friction force is in perpendicular direction to the direction of carís velocity (it is towards the center of the circle). So, Newtonís 2nd law: F_net = mv2/R. Hint 5: friction force is the only force acting on the car in horizontal direction: F_net = F_fr.

Given
Radius , r = 100 m
Height , h = 1 m
Width ,w = 2 m
We will find angle of banking
sinθ = 1 / 2
θ = 300
The speed of the car is
v = gr tan30
= 10 m/s^2 * 100 m *0.5773
v = 24 m/s
53.686471 mph

That answer is wrong, it has to be in MPH btw, please help me.

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