Posted by Peter Adrian Ngo on Sunday, March 20, 2011 at 3:38am.
One car passes the other at a relative rate of 5 mph = 7.333 ft/s, and must change the distance between them by 60 + 60 + 15 = 135 feet before returning to the right side of the dividing line. The time required for the entire passing maneuver is 135/7.333 = 18.41 s. An oncoming car approaches the passing car at a relative rate 100 mph = 146.7 ft/s. The clear length of road required to avoid a collision is
146.7 x 18.41 = 2700 feet, which is over half a mile.
Related Questions
physics - Just as a car starts to accelerate from rest with an acceleration of 1...
physics - a car, moving at 100 mi/hr, passes a stationary police car whose siren...
Physics - A car travels at 64 mi/h when the brakes are suddenly applied. ...
Physics - An 893 kg car passes over a bump in a road that follows the arc of a ...
physics - As a traffic light turns green, a waiting car starts with a constant ...
Physics - A truck travels at a constant speed of 28.0 m/s in the fast lane of a ...
physics - A car travels along a straight stretch of road. It proceeds for 11.9 ...
physics - A car travels along a straight stretch of road. It proceeds for 14 mi ...
physics - A car travels along a straight stretch of road. It proceeds for 15 mi ...
physics - A car travels along a straight stretch of road. It proceeds for 15 mi ...
For Further Reading