A 680 newton student runs up a flight of stairs 3.5 m high in 11.4 seconds. The student takese 8.5 seconds to run up the same flight of stairs during a second trial.

1)Find the work done by the 680 N student in climbing the stairs

2) Determine the power developed by the student during the 11.4 second climb.

3. Write 1-2 sentences: Compare the power developed by the student climbing the stairs in 11.4 seconds to the power developed during the 8.5 second trial.

I need help setting up the problem in 1 and 2. #3 I don't understand what is wanted for the comparison.

work done = 680*3.5 Joules

first time:
power = work/time = 680*3.5/11.4 Watts

second time:
power = 680*3.5/8.5

To solve the problem, we need to use the formulas for work, power, and comparison of power.

1) The work done by an object is calculated by multiplying the force applied by the distance covered. In this case, the force is 680 N, and the distance covered is 3.5 m. Therefore, the work done by the student is:

Work = Force × Distance
Work = 680 N × 3.5 m

2) Power is defined as the rate at which work is done or energy is transferred. It is calculated by dividing the work done by the time taken. For the first trial, the time taken is 11.4 s. So, the power developed by the student during this climb is:

Power = Work / Time
Power = (680 N × 3.5 m) / 11.4 s

For the comparison in question 3, we need to compare the power developed by the student during the 11.4 seconds climb to the power developed during the 8.5 seconds trial.

1) To find the work done by the student in climbing the stairs, we can use the formula:

Work = Force * Distance * Cosine(θ)

Where:
- Force (F) = 680 Newtons, the force exerted by the student
- Distance (D) = 3.5 meters, the height of the stairs
- θ (theta) = 0 degrees, since the force is applied vertically and the stairs are also vertical

Now let's plug in the values and calculate the work:

Work = 680 N * 3.5 m * Cosine(0°)

Note that the cosine of 0 degrees is 1, so we can simplify the equation:

Work = 680 N * 3.5 m * 1
Work = 2380 Joules

Therefore, the work done by the student in climbing the stairs is 2380 Joules.

2) To determine the power developed by the student during the 11.4 second climb, we can use the formula:

Power = Work / Time

We've already calculated the work as 2380 Joules. Now let's plug in the time:

Power = 2380 J / 11.4 s
Power ≈ 208.77 Watts

Therefore, the power developed by the student during the 11.4 second climb is approximately 208.77 Watts.

3) The comparison of power developed by the student in the two trials can be done by calculating the power during the second trial (8.5 seconds) using the same formula as in the previous step.

Power (second trial) = Work / Time (second trial)

Obtain the work by using the same formula as before: Work = Force * Distance * Cosine(θ), and the values given for the force (680 N) and distance (3.5 m). Then divide the work by the time (8.5 seconds) provided for the second trial:

Power (second trial) = Work / 8.5 s

Finally, you can compare the power developed by the student in both trials.

IT IS A RATE