you are correct on the points 1,24 adn 2,45
The first part, I do not understand what you were doing.
y=3x^2 + 12x + 9
you are correct that when x = 0, y = 9 so (0,9) is on it
However I do not know what else you are doing.
I generally complete the square to find the axis of symmetry
3x^2 + 12x + 9 = y
get one by x^2 so divide by 3
x^2 + 4 x + 3 = y/3
subtract 3 from both sides
x^2+4x = y/3 - 9/3 =
add (half of 4)^2 to both sides
x^2 + 4 x + 4 = y/3 -9/3 + 12/3
(x+2)^2 = (1/3)(y+3)
vertex at (-2, -3)
vertical axis of symmetry at x = -2
Well, I'm trying to find two different points by changing the x value since I need to graph these points and then reflect it. I hope this helps you a little.
ok, well reflect it about the line x = -2
and the bottom is at (-2,-3)
Your (1,24) and your (2,45) are fine
first point is the bottom (-2,-3)
next is your (1,24)
the reflection of that about x = -2 is
3 to the left of -2 which is (-5,24)
next do your (2,45)
that is four to the right of the line of symmetry so go four to the left of -2 to -6
this might help:
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