Saturday
April 19, 2014

Homework Help: Algebra

Posted by David on Saturday, March 19, 2011 at 7:52pm.

Hello. I am trying to solve quadratic functions but I'm having difficulty understanding. Here is my work so far...

y=3x^2 + 12x + 9
12/6 = -2 = y
3(-2)^2 + 12(-2) + 9 = -3
x=0 y=9 (0,9)

Would I just plug in 1 and 2 for x and then reflect it while i'm graphing?

So, if I do that, should it come out...

x=1
-----
y=3(1)^2 + 12(1) + 9
y=3+12+9
y=24 (1,24)

x=2
------
y=3(2)^2 + 12(2) + 9
y=12+24+9
y=45 (2,45)

Would this be correct?

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