Posted by **katie** on Saturday, March 19, 2011 at 6:31pm.

If 74.5 grams of a hot metal was added to 56.4 grams of water and the temperature of the water rose from 20.4 to 33.4 degrees, how many KJ of energy was lost by the hot metal?

- chemistry -
**DrBob222**, Saturday, March 19, 2011 at 6:36pm
q = mass water x specific heat water x (Tfinal-Tinitial)

- chemistry -
**katie**, Sunday, March 20, 2011 at 12:35am
i need help setting this problem up. i don't understand which numbers go where

- chemistry -
**DrBob222**, Sunday, March 20, 2011 at 1:02pm
There is no setting up. Just substitute the numbers into the equation.

q = your answer.

mass water = 56.4g in the problem.

specific heat water = look this up in your text or notes. It is 4.184 J/gram I think.

Tfinal = 33.4 from the problem.

Tinitial = 20.4 from the problem.

q will be in joules, the problem asks for kJ; therefore, divide the answer you get by 1000 to convert J to kJ.

## Answer This Question

## Related Questions

- chemistry - If 74.5 grams of a hot metal was added to 56.4 grams of water and ...
- Physics - 400 grams of a metal at 300 C is added to 100 grams of of water at 20...
- Chemistry - A 11.6 g sample of an unknown metal was heated to 100.0 oC and then...
- Chemistry - A 230-gram sample of metal at 82 degrees centigrade is added to 632 ...
- college Chemistry - 1. If 25 grams of Iron (III) hydroxide is dissolved in a ...
- Physical Science - A hot metal spoon with a mass of 77.0 grams and a temperature...
- college chem - In this experiment a hot metal block at 100oC is added to cold ...
- Chemistry - What is the final temperature and physical state of water when 250 ...
- Physics - How many grams of ice must be added to 100 grams of water at 60 ...
- chemistry - if 10 grams of metal A changes the temperature of 10 grams of water...

More Related Questions