Posted by billy on Saturday, March 19, 2011 at 6:23pm.
how do you solve the initial value problem by using separation of variables dy/dx=1+x/(sqrt of y), y(2)=9

calculus (())  MathMate, Saturday, March 19, 2011 at 6:53pm
Watch missing parentheses, please.
Parentheses are needed to enclose numerators and denominators, otherwise additions and subtractions will take place after the division.
Separate the variables,
dy/dx = (1+x)/sqrt(y)
sqrt(y)dy = (1+x)dx
Integrate:
(2/3)y^(3/2) = x + x²/2 + C
y = [(3/2)(x+x²/2+C)]^(2/3)
from which we can solve for C=14.
so
y(x)=[(3/2)(x+x²/2+14)]^(2/3)
Please check all arithmetic.
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