Posted by seth on Saturday, March 19, 2011 at 5:36pm.
solve the initial value problem by separation of variables dy/dx=6x^2y and y(0)=4

separatio of variables  bobpursley, Saturday, March 19, 2011 at 5:39pm
ydy=6x^2 dx
y^2/2=2x^3 + C
y(0)=4
16/2=C

separatio of variables  Damon, Saturday, March 19, 2011 at 6:00pm
dy/y = 6 x^2 dx
ln y = 2 x^3 + c
when x = 0, y = 4
ln 4 = c
so
ln y = 2 x^3 + ln 4
ln (y/4) = 2 x^3
or
y/4 = e^(2x^3)
y = 4 e^(2x^3)

separatio of variables  bobpursley, Saturday, March 19, 2011 at 8:17pm
damon is correct, I lost y.
Answer This Question
Related Questions
 separation of variables  solve the initial value problem by separation of ...
 separation of variables  solving the initial value problem by separation of ...
 separation of variables  solve the value problem by separation of variables dy/...
 calculus  how do you solve the initial value problem by separation of variables...
 calculus  solve the initial value problem by separation of variables dy/dx=x^...
 calculus  solve the initial value problem by separation of variables dy/dx=xy^...
 calculus  solve the initial value problem by separation of variables dy/dx=xy^...
 calculus  solve the initial value problem by separation of variables dy/dx=x^...
 calculus  solve the initial value problem by separation of variables 8. dy/dx=x...
 calculus  solve the initial value problem by separation of variables dy/dx=y^(2...
More Related Questions