How many grams of SO2 can be produced from 100g of S and excess O2
A sample problem. Just follow the steps. Post your work if you get stuck.
http://www.jiskha.com/science/chemistry/stoichiometry.html
Oh, sulfur and oxygen gettin' together to produce some sulfur dioxide, huh? Well, let me crunch some numbers for ya.
The molar mass of sulfur (S) is approximately 32 grams per mole, and the molar mass of sulfur dioxide (SO2) is about 64 grams per mole. So, for every mole of S, you need one mole of SO2.
Since the molar mass ratio is 1:1, we can say that if you have 100 grams of S, it means you have 100/32 = 3.125 moles of sulfur.
And since the ratio is 1:1, you'll end up with 3.125 moles of sulfur dioxide.
Now, to calculate the mass of SO2, we multiply the moles by the molar mass:
Mass of SO2 = 3.125 moles x 64 grams/mole = 200 grams
So, from 100 grams of sulfur and excess oxygen, you can produce 200 grams of sulfur dioxide. Whew, that's a lot of SO2! Better open a window!
To determine how many grams of sulfur dioxide (SO2) can be produced from 100 grams of sulfur (S) and an excess of oxygen (O2), we need to find the balanced chemical equation for the reaction between sulfur and oxygen, and then calculate the molar mass and stoichiometry.
The balanced chemical equation for the reaction is:
2S + 3O2 -> 2SO2
From the equation, we can see that 2 moles of sulfur react with 3 moles of oxygen to produce 2 moles of sulfur dioxide.
Step 1: Calculate the molar mass of sulfur (S):
The molar mass of sulfur is 32.06 g/mol.
Step 2: Calculate the number of moles of sulfur (S) in 100 grams:
Number of moles of sulfur (S) = Mass of sulfur (S) / Molar mass of sulfur (S)
Number of moles of sulfur (S) = 100 g / 32.06 g/mol
Number of moles of sulfur (S) = 3.12 mol
Step 3: Using the stoichiometry of the balanced equation, we can determine the number of moles of sulfur dioxide (SO2) produced:
According to the balanced equation, the molar ratio between sulfur (S) and sulfur dioxide (SO2) is 2:2.
So, the number of moles of sulfur dioxide (SO2) produced is equal to the number of moles of sulfur (S).
Number of moles of sulfur dioxide (SO2) = 3.12 mol
Step 4: Calculate the mass of sulfur dioxide (SO2) produced:
Mass of sulfur dioxide (SO2) = Number of moles of sulfur dioxide (SO2) * Molar mass of sulfur dioxide (SO2)
Mass of sulfur dioxide (SO2) = 3.12 mol * 64.06 g/mol
Mass of sulfur dioxide (SO2) = 199.99 g
Therefore, 100 grams of sulfur (S) can produce 199.99 grams of sulfur dioxide (SO2) when reacted with an excess amount of oxygen (O2).
To find out how many grams of SO2 can be produced from 100g of S and excess O2, you need to consider the balanced chemical equation for the reaction between sulfur (S) and oxygen gas (O2) to form sulfur dioxide (SO2).
The balanced chemical equation is:
2S + 3O2 → 2SO2
From the balanced equation, we can see that 2 moles of sulfur (S) react with 3 moles of oxygen gas (O2) to produce 2 moles of sulfur dioxide (SO2).
To calculate the grams of SO2 produced, we can follow these steps:
Step 1: Convert 100g of sulfur (S) to moles.
To do this, we can use the molar mass of sulfur (S), which is approximately 32.07 g/mol.
Number of moles of S = Mass of S / Molar mass of S
Number of moles of S = 100g / 32.07 g/mol
Number of moles of S ≈ 3.12 mol (approximately)
Step 2: Calculate the moles of SO2 produced.
Since the ratio of S to SO2 in the balanced equation is 2 moles of S to 0.5 moles of SO2 (2:0.5), we can use a proportion to find the moles of SO2.
Number of moles of SO2 = (Number of moles of S / 2) * (0.5 moles of SO2 / 1 mole of S)
Number of moles of SO2 = (3.12 mol / 2) * (0.5 mol / 1 mol)
Number of moles of SO2 ≈ 0.78 mol (approximately)
Step 3: Convert moles of SO2 to grams.
To do this, we can use the molar mass of SO2, which is approximately 64.06 g/mol.
Mass of SO2 = Number of moles of SO2 × Molar mass of SO2
Mass of SO2 = 0.78 mol × 64.06 g/mol
Mass of SO2 ≈ 50g (approximately)
Therefore, approximately 50 grams of SO2 can be produced from 100 grams of S and excess O2.