Posted by Amy on Saturday, March 19, 2011 at 10:00am.
the original problem was:
(sin x + cos x)^2 + (sin x  cos x)^2 = 2
steps too please
I got 1 for (sin x + cos x)^2
but then what does (sin x  cos x)^2 become since it's minus?

Math  Reiny, Saturday, March 19, 2011 at 12:07pm
see reply to your earlier post of this question

Math  Anonymous, Saturday, March 19, 2011 at 5:06pm
(a+b)^2=a^2+2*a*b+b^2
(ab)^2=a^22*a*b+b^2
[sin(x)+cos(x)]^2=
[sin(x)]^2 +2*sin(x)*cos(x)+ [cos(x)]^2
[sin(x)cos(x)]^2=
[sin(x)]^2 2*sin(x)*cos(x)+ [cos(x)]^2
[sin(x)+cos (x)]^2+[sin(x)cos (x)]^2=
[sin(x)]^2 +2*sin(x)*cos(x)+ [cos(x)]^2+
[sin(x)]^2 2*sin(x)*cos(x)+ [cos(x)]^2=
+[cos(x)]^2+[cos(x)]^2+[sin(x)]^2+[cos(x)]^2=
2*[[sin(x)]^2+[cos(x)]^2]=2*1=2
Becouse: [sin(x)]^2+[cos(x)]^2=1 
Math  Anonymous, Saturday, March 19, 2011 at 5:08pm
[sin(x)+cos(x)]^2=
[sin(x)]^2 +2*sin(x)*cos(x)+ cos(x)]^2
[sin(x)cos(x)]^2=
[sin(x)]^2 2*sin(x)*cos(x)+ cos(x)]^2