a pennant is shaped like an isosceles triangle.the short side is 14in.long and is half the length of each longer side.find the perimeter
I solved the last one. Now it's your turn. Draw it out if you need to.
And I'll assume you know what 14 x 2 is.
28
To find the perimeter of the isosceles triangle shaped like a pennant, we need to find the lengths of all three sides and add them together.
Let's start by finding the lengths of the longer sides. We are given that the short side of the triangle is 14 inches long, and it is half the length of each longer side.
Let's define the longer side length as 'L'.
Since the short side is half the length of each longer side, we can express it as L/2.
So, we have the equation L/2 = 14 inches.
To find the value of L, we can multiply both sides of the equation by 2:
L/2 * 2 = 14 inches * 2
L = 28 inches
Now that we know the length of each longer side (L = 28 inches), we can find the perimeter of the triangle.
The perimeter of any polygon is simply the sum of the lengths of all its sides.
In this case, the short side is given as 14 inches, and the two longer sides are each 28 inches. So, to calculate the perimeter:
Perimeter = 14 inches + 28 inches + 28 inches
Perimeter = 70 inches + 28 inches
Perimeter = 98 inches
Therefore, the perimeter of the isosceles triangle shaped like a pennant is 98 inches.