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September 21, 2014

September 21, 2014

Posted by **Amy** on Friday, March 18, 2011 at 9:01pm.

only simplify one side to equal csc

so far I got this far:

[((cos)(sin))/(cos)] + [((cos)(cos))/(sin)] = csc

I don't know what to do next

- Math -
**bobpursley**, Friday, March 18, 2011 at 9:17pmthen on the left..

sin+cos^2/sin=sin+(1-sin^2)sin=sin+csc-sin=csc

- Math -
**Reiny**, Friday, March 18, 2011 at 9:19pmYou will need a common denominator of sinxcosx in your fraction to get

LS = cosx(sin^2x /(sinxcosx) + cos^2x/(sinxcosx))

= cosx (sin^2x + cos^2x)/(sinxcosx)

= cosx(1)/(sinxcosx)

= 1/sinx

= cscx

BTW you cannot just use the operators, there has to be some "angle" after it

e.g. to say tan = sin/cos is not acceptable and mathematical gibberish.

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