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March 1, 2015

March 1, 2015

Posted by **joseph** on Friday, March 18, 2011 at 8:56pm.

- calculus -
**Damon**, Saturday, March 19, 2011 at 3:23amI am guessing that you mean sec^2 and left out parentheses

du/dt=(2t+sec^2t)/2u, u(0)=-5

2 u du = 2 t dt + sec^2 t dt

u^2 = t^2 + tan t + c

when t = 0, u = -5

25 = c

u^2 = t^2 + tan t + 25

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