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calculus

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solve the initial value problem by seperation of variables du/dt=2t+sec2t/2u, u(0)=-5

  • calculus - ,

    I am guessing that you mean sec^2 and left out parentheses

    du/dt=(2t+sec^2t)/2u, u(0)=-5

    2 u du = 2 t dt + sec^2 t dt

    u^2 = t^2 + tan t + c

    when t = 0, u = -5

    25 = c

    u^2 = t^2 + tan t + 25

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