Posted by mike on Friday, March 18, 2011 at 8:56pm.
solve the initial value problem by seperation of variables du/dt=2t+sec2t/2u, u(0)=5

calculus ((()))  MathMate, Saturday, March 19, 2011 at 12:15am
The following equation is separable (please check this is the same as your question after adding appropriate parentheses):
du/dt = (2t+sec(2t)) / (2u)
transpose terms to get:
(2u)du = (2t+sec(2t))dt
Integrate both sides (do not forget the integration constant) and substitute u(0)=5 (i.e. u(t)=5, when t=0) to evaluate the integration constant.
Post your answer for a check if you wish.
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