Posted by **mike** on Friday, March 18, 2011 at 8:56pm.

solve the initial value problem by seperation of variables du/dt=2t+sec2t/2u, u(0)=-5

- calculus ((())) -
**MathMate**, Saturday, March 19, 2011 at 12:15am
The following equation is separable (please check this is the same as your question after adding appropriate parentheses):

du/dt = (2t+sec(2t)) / (2u)

transpose terms to get:

(2u)du = (2t+sec(2t))dt

Integrate both sides (do not forget the integration constant) and substitute u(0)=-5 (i.e. u(t)=-5, when t=0) to evaluate the integration constant.

Post your answer for a check if you wish.

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