Post a New Question

calculus

posted by on .

solve the initial value problem by seperation of variables du/dt=2t+sec2t/2u, u(0)=-5

  • calculus ((())) - ,

    The following equation is separable (please check this is the same as your question after adding appropriate parentheses):

    du/dt = (2t+sec(2t)) / (2u)

    transpose terms to get:

    (2u)du = (2t+sec(2t))dt

    Integrate both sides (do not forget the integration constant) and substitute u(0)=-5 (i.e. u(t)=-5, when t=0) to evaluate the integration constant.

    Post your answer for a check if you wish.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question