Posted by **mike** on Friday, March 18, 2011 at 8:56pm.

solve the initial value problem by seperation of variables du/dt=2t+sec2t/2u, u(0)=-5

- calculus ((())) -
**MathMate**, Saturday, March 19, 2011 at 12:15am
The following equation is separable (please check this is the same as your question after adding appropriate parentheses):

du/dt = (2t+sec(2t)) / (2u)

transpose terms to get:

(2u)du = (2t+sec(2t))dt

Integrate both sides (do not forget the integration constant) and substitute u(0)=-5 (i.e. u(t)=-5, when t=0) to evaluate the integration constant.

Post your answer for a check if you wish.

## Answer This Question

## Related Questions

- calculus - solve the initial value problem by seperation of variables du/dt=2t+...
- calculus - how do you solve the initial value problem by separation of variables...
- calculus - solve the initial value problem by separation of variables dy/dx=-x^...
- calculus - solve the initial value problem by separation of variables dy/dx=-xy^...
- calculus - solve the initial value problem by separation of variables dy/dx=-xy^...
- calculus - solve the initial value problem by separation of variables dy/dx=-x^...
- calculus - solve the initial value problem by separation of variables 8. dy/dx=x...
- calculus - solve the initial value problem by separation of variables dy/dx=y^(2...
- calculus - how do you solve the initial value problem by using separation of ...
- calculus - how do you solve the initial value problem by using separation of ...

More Related Questions