calculus
posted by Janet on .
Did I do this problem right?
Find the first and second derativesimplify your answer.
y=xtanx
y'= (x)(sec^2 x)+(tanx)(1)
y'= xsec^2 x + tanx
y"= (x)(2secx)(secxtanx)+sec^2 x + sec^2 x
y"=2xsec^2 x tanx + 2 sec^2 x

= 2 sec^2x(x tan x + 1)