Posted by **Janet** on Friday, March 18, 2011 at 2:25am.

Did I do this problem right?

Find the first and second derative-simplify your answer.

y=xtanx

y'= (x)(sec^2 x)+(tanx)(1)

y'= xsec^2 x + tanx

y"= (x)(2secx)(secxtanx)+sec^2 x + sec^2 x

y"=2xsec^2 x tanx + 2 sec^2 x

- calculus -
**Damon**, Friday, March 18, 2011 at 7:10am
= 2 sec^2x(x tan x + 1)

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