Posted by **Mandy** on Thursday, March 17, 2011 at 6:27pm.

The center of a 1.50 diameter spherical pocket of oil is 1.20 beneath the Earth's surface. Estimate by what percentage directly above the pocket of oil would differ from the expected value of for a uniform Earth? Assume the density of oil is 800 kg/m^3. Solve for delta g/ g = %

## Answer This Question

## Related Questions

- Physics - The center of a 1.50 diameter spherical pocket of oil is 1.20 beneath ...
- Physics Problem 6.20 - The center of a 1.10 diameter spherical pocket of oil is ...
- physics - The center of a 1.00km diameter spherical pocket of oil is 1.00kkm ...
- Physics Problem 6.20 - The center of a 1.40 km diameter spherical pocket of oil ...
- Physics - The center of a 1.10km diameter spherical pocket of oil is 1.10km ...
- Phsyics - The center of a 1.10km diameter spherical pocket of oil is 1.10km ...
- College Physics - When searching for gold, measurements of g can be used find ...
- physics - Question 6) Oil and gas exploration companies find new underground ...
- physics - one liter (1000cm3) of oil is spiled onto a smooth lake. if the oil ...
- AP Physics - You can obtain a rough estimate of the size of a molecule by the ...

More Related Questions