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August 29, 2014

August 29, 2014

Posted by **kiksy** on Thursday, March 17, 2011 at 12:13am.

i startted the problem below by writing a sigma notation

of

sigma[(2^(n+1))/((n+1)!)]

QUESTION:

how do i find the sum of 2+(4/2!)+(8/3!)+(16/4!)+...

was my attempt wrong, or how do i go from here? thank you!

- math -
**MathMate**, Thursday, March 17, 2011 at 11:56amExpress the individual elements of each term in terms of i.

For the 3rd term, i=3, then

8/3!=2*³/3! = 2³/i!

Verify with another term:

for i=4,

2^i/i!=16/4! = 4th term, OK

Check the first term (which does not have the same form), i=1

2^1/1! = 2/1 = 2 OK

So the sum would be:

Σ2^i /i! for i=1 to ∞

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