Posted by **kiksy** on Thursday, March 17, 2011 at 12:13am.

hi

i startted the problem below by writing a sigma notation

of

sigma[(2^(n+1))/((n+1)!)]

QUESTION:

how do i find the sum of 2+(4/2!)+(8/3!)+(16/4!)+...

was my attempt wrong, or how do i go from here? thank you!

- math -
**MathMate**, Thursday, March 17, 2011 at 11:56am
Express the individual elements of each term in terms of i.

For the 3rd term, i=3, then

8/3!=2*³/3! = 2³/i!

Verify with another term:

for i=4,

2^i/i!=16/4! = 4th term, OK

Check the first term (which does not have the same form), i=1

2^1/1! = 2/1 = 2 OK

So the sum would be:

Σ2^i /i! for i=1 to ∞

## Answer this Question

## Related Questions

- math - hi i startted the problem below by writing a sigma notation of sigma[(2^(...
- Algebra - find the indicated sum not sure how to type the sigma sign, but here ...
- math - I just need help with this. Write the series in sigma notation. 1/4 + 1/2...
- math - I just need help with this. Write the series in sigma notation. 1/4 + 1/2...
- Maths - Express the sum using summation notation: 1 - 1/2 + 1/3 - 1/4 + 1/5...
- Maths - Express the sum using summation notation: 1 - 1/2 + 1/3 - 1/4 + 1/5...
- Maths - Express the sum using summation notation: 1 - 1/2 + 1/3 - 1/4 + 1/5...
- sigma notation - find the value of the sum n sigma i=1 (2-5i)
- Pre-CalcPlease check - Please check: 1.Write in expanded form: this is a sigma ...
- Math - Write the sum (in sigma notation) 1 + 3/2 + 2 + 5/2 + 3 + 7/2 + 4 Sigma ...

More Related Questions