what is the equation for the reaction of Cu(NH3)subscript2(SO4) with NaOH?
To determine the chemical equation for the reaction between Cu(NH3)2(SO4) and NaOH, we need to understand the solubility rules and the possible reactions that can occur.
First, let's break down the chemical formula: Cu(NH3)2(SO4) represents copper(II) ammine sulfate, where Cu is the symbol for copper, NH3 represents ammonia ligands, and SO4 is the sulfate ion.
NaOH represents sodium hydroxide, which dissociates into Na+ (sodium ion) and OH- (hydroxide ion) in a solution.
Now, let's proceed with the reaction:
Cu(NH3)2(SO4) + 2NaOH ->
When sodium hydroxide reacts with copper(II) ammine sulfate, it displaces the sulfate ion (SO4) and forms a new compound known as copper(II) hydroxide solid (Cu(OH)2).
The balanced equation for the reaction is:
Cu(NH3)2(SO4) + 2NaOH -> Cu(OH)2 + 2Na(NH3)2(SO4)
So, 1 mole of Cu(NH3)2(SO4) reacts with 2 moles of NaOH to produce 1 mole of Cu(OH)2 and 2 moles of Na(NH3)2(SO4).