There are 10 girls and 6 boys in a class. The teacher randomly draws one student's name and then draws another. What is the probability that the first name drawn will be a boy and the second will be a girl?

%23

Pr(b,g)=6/16*10/15

25%

To find the probability of drawing a boy first and a girl second, we need to determine two things: the total number of possible outcomes and the number of favorable outcomes.

First, let's calculate the total number of possible outcomes. The teacher is drawing two names, so there are 16 students in total. When drawing the first name, any of the 16 students can be selected. After the first name is drawn, there are now 15 students remaining for the second draw. Therefore, the total number of possible outcomes is 16 * 15 = 240.

Now, let's determine the number of favorable outcomes. Since we want a boy to be drawn first and a girl to be drawn second, there are 6 boys and 10 girls to choose from for each draw. So, the number of favorable outcomes is 6 (for the first draw) * 10 (for the second draw) = 60.

Finally, to find the probability, we divide the number of favorable outcomes by the total number of possible outcomes: 60 / 240 = 1/4.

Therefore, the probability of drawing a boy first and a girl second is 1/4 or 0.25, which can also be expressed as 25%.

''SUC''

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