calculus
posted by redgy on .
find f'(x) for the following:
f(x)= cos^5(4x19)
I keep getting 20cos^4(4x19)sin, but the answer is supposed to be
20cos^4(4x19)sin(4x19). I can't seem to get there with derivatives

never mind. I figured it out. That is the correct anser, I didn't carry through with the derivitives.