Posted by **redgy** on Wednesday, March 16, 2011 at 6:39pm.

find f'(x) for the following:

f(x)= cos^5(4x-19)

I keep getting 20cos^4(4x-19)sin, but the answer is supposed to be

-20cos^4(4x-19)sin(4x-19). I can't seem to get there with derivatives

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