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Posted by on Wednesday, March 16, 2011 at 6:39pm.

find f'(x) for the following:
f(x)= cos^5(4x-19)
I keep getting 20cos^4(4x-19)sin, but the answer is supposed to be
-20cos^4(4x-19)sin(4x-19). I can't seem to get there with derivatives

  • calculus - , Wednesday, March 16, 2011 at 6:45pm

    never mind. I figured it out. That is the correct anser, I didn't carry through with the derivitives.

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