You and three of your friends are part of a group of 10 potential jurors. What is the probability that you and your 3 friends are the last 4 people chosen?
Suppose the names of you and your 3 friends are
A, B, C, and D
and X is anybody else
so one correct order of choosing would be
XXXXXXABCD
but the order of ABCD could be arranged in 4! or 24 ways
the prob of XXXXXXABCD
= (6/10)(5/9)(4/8)(3/7)(2/6)(1/5)(1/4)(1/3)(1/2)(1/1) = 6!/10!
but there are 24 of these
prob of your event = 24(6!/10!) = appr. .00476