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Posted by on Wednesday, March 16, 2011 at 12:04am.

Hooker's law. The distance d when a spring is stretched by a hanging object varies directly as the weight w of the object. If the distance is 39cm when the weight is 3kg, what is the distance when the weight is 9kg?

Thank you, before hand.

  • Algebra II - , Wednesday, March 16, 2011 at 11:56am

    39/3 = 13 cm/kg, the spring "rate" of the spring.

    Therefore, the d for 9kg is

    d = 13cm/kg x 9kg = 117cm.

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