Posted by darren on Tuesday, March 15, 2011 at 11:11pm.
...............HA ==> H^+ + A^-
begin.........0.04M....0......0
change..........-x......+x.....+x
final.......0.04-x......x.......x
Ka = (H^+)(A^-)/(HA)
You know pH, convert to (H^+) and that will be x. Substitute into Ka expression and solve for Ka.
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