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Posted by **maria** on Tuesday, March 15, 2011 at 10:51pm.

uniform rate of 0.82 m/s2.

What is the magnitude of the car’s displace-

ment as it accelerates uniformly from a speed

of 85 km/h to one of 95 km/h?

Answer in units of m.

- physics -
**drwls**, Wednesday, March 16, 2011 at 2:23amThe 10 km/h velocity change is 2.78 m/s

The time required to accomplish that velocity change is (deltaV)/a

= (2.78 m/s)/0.82 m/s^2 = 3.39 s

The displacement will be the average velocity multiplied by that time.

X = (90 km/h)*3.39 s* 1h/3600 s

= ___ meters

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