Write a balanced chemical equation (molecular equation). Write a total ionic equation. write a net ionic equation.

(NH4)2 SO4(aq)+Na2CO3(aq) -->

Surely you know how to do parts of this. What part do you not understand and what is the principle problem you are having?

I do not know how to get the products from the left half of the equation. After that I am pretty much fine, except for I don't know how to determine the charge of certain compounds.

To write the balanced chemical equation, total ionic equation, and net ionic equation, we need to first identify the reactants and products in the given chemical equation:

Reactants:
(NH4)2SO4(aq) - ammonium sulfate
Na2CO3(aq) - sodium carbonate

Product:
NH4+ (aq) - ammonium ion
SO4^2- (aq) - sulfate ion
2Na+ (aq) - sodium ion
CO3^2- (aq) - carbonate ion

Now let's proceed to write the balanced chemical equation:

(NH4)2SO4(aq) + Na2CO3(aq) → 2NH4+(aq) + SO4^2-(aq) + 2Na+(aq) + CO3^2-(aq)

This equation represents the reaction between ammonium sulfate and sodium carbonate.

Next, let's write the total ionic equation. The total ionic equation shows all the ions present in the reaction:

(NH4)2SO4(aq) + 2Na+(aq) + CO3^2-(aq) → 2NH4+(aq) + SO4^2-(aq) + 2Na+(aq) + CO3^2-(aq)

Note that in the total ionic equation, all the soluble compounds are dissociated into their respective ions.

Finally, we can write the net ionic equation. The net ionic equation eliminates the spectator ions that do not participate in the reaction:

(NH4)2SO4(aq) + CO3^2-(aq) → 2NH4+(aq) + SO4^2-(aq)

In the net ionic equation, the spectator ions Na+ and Na+(aq) are removed because they are present on both sides of the equation and do