how do you solve:
-3y=3x-9
and
2x-4y=12
and
-3x=2y
I'll do the first one:
-3y=3x-9
Divide by -3 on both sides:
-3y/(-3)=(3x-9)/-3
y=-x+3
To solve the given system of equations, we can use various methods, such as substitution, elimination, or graphing. Let's go through each equation one by one:
1. -3y = 3x - 9
To solve for y, we can use the method of isolating the y-term. Divide both sides of the equation by -3, which will give us:
y = (-3x + 9) / 3
Now we have an expression for y in terms of x.
2. 2x - 4y = 12
We can solve this equation using the same method by isolating the y-term. First, subtract 2x from both sides of the equation:
-4y = -2x + 12
Next, divide both sides of the equation by -4 to isolate y:
y = (-2x + 12) / -4
Now we have an expression for y in terms of x.
3. -3x = 2y
Similarly, we need to solve for y. First, divide both sides of the equation by 2:
(-3x) / 2 = y
Rearranging the terms, we have:
y = (-3/2)x
Now we have an expression for y in terms of x.
Now that we have expressions for y in terms of x in all three equations, we can substitute these expressions into each other to find the solution to the system of equations.