what is the concentration in percent by volume of 25.0 mL of rubbing alcohol (C3H7OH) diluted to a volume of 200.0 mL with water? I got 12.5% am i correct??
To find the concentration in percent by volume, we need to divide the volume of the solute (rubbing alcohol) by the total volume of the solution (rubbing alcohol + water), then multiply by 100.
Given:
Volume of rubbing alcohol (C3H7OH) = 25.0 mL
Volume of water = 200.0 mL
First, calculate the total volume of the solution:
Total volume = Volume of rubbing alcohol + Volume of water
Total volume = 25.0 mL + 200.0 mL
Total volume = 225.0 mL
Now, calculate the concentration in percent by volume:
Concentration (%) = (Volume of rubbing alcohol / Total volume) × 100
Concentration (%) = (25.0 mL / 225.0 mL) × 100
Concentration (%) ≈ 11.11%
Therefore, the correct concentration in percent by volume is approximately 11.11%, not 12.5%.
To calculate the concentration in percent by volume, we need to use the formula:
Percent by volume = (Volume of solute / Volume of solution) * 100
In this case, the solute is rubbing alcohol (C3H7OH), which has a volume of 25.0 mL, and the solution is the mixture of rubbing alcohol and water, which has a total volume of 200.0 mL.
Plugging the values into the formula:
Percent by volume = (25.0 mL / 200.0 mL) * 100
Calculating the expression:
Percent by volume = 0.125 * 100
Percent by volume = 12.5
Therefore, your answer of 12.5% is correct! The concentration in percent by volume of the rubbing alcohol diluted to a volume of 200.0 mL with water is indeed 12.5%.
Yes Your Are Right.!
(25.0mL/200.0mL)(100)=12.5%