what is the molarity of solution made from the equivalent of 125 g of sodium nitrate in 1.0 l of solution
To determine the molarity of a solution, you need to know the number of moles of solute (in this case, sodium nitrate) and the volume of the solution. Here are the steps to find the molarity:
1. Calculate the number of moles of sodium nitrate:
- Determine the molar mass of sodium nitrate (NaNO3). The molar mass can be found by adding up the atomic masses of each element in the compound: Na (sodium) has a molar mass of 22.99 g/mol, N (nitrogen) has a molar mass of 14.01 g/mol, and O (oxygen) has a molar mass of 16.00 g/mol. Add them together:
Molar mass of NaNO3 = (22.99 g/mol + 14.01 g/mol + (16.00 g/mol × 3)) = 85.00 g/mol
- Calculate the number of moles using the formula:
Moles = Mass / Molar Mass
Moles of NaNO3 = 125 g / 85.00 g/mol
2. Calculate the molarity:
- Molarity (M) is defined as moles of solute per liter of solution. Since you have 1.0 L of solution, the molarity is:
Molarity = Moles / Volume of solution
Molarity = (125 g / 85.00 g/mol) / 1.0 L
Now you can calculate the molarity of the solution.