Posted by Jake on Tuesday, March 15, 2011 at 2:28pm.
A hotair balloon is 180 ft above the ground when a motorcycle passes directly beneath it (travelling in a straight line on a horizontal road) going at a constant speed of 60 ft/s. If the balloon is rising vertically at a rate of 15 ft/s, what is the rate of change of the distance between the motorcycle and the balloon 20 seconds after the motorcycle was directly beneath the balloon.

Calculus  bobpursley, Tuesday, March 15, 2011 at 2:55pm
draw the figure, a right triangle. figure out distances after 20seconds.
let horizontal distance be x, height be h, and d the slant distance.
d^2=h^2+x^2
2d dd/dt= 2h dh/dt+2x dx/dt
solve for dd/dt, you know all else.
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