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April 20, 2014

April 20, 2014

Posted by **Leo** on Tuesday, March 15, 2011 at 1:03am.

2. A 32-kg girl is bouncing on a trampoline. During a certain interval after she leaves the surface of the trampoline, her kinetic energy decreases to 205 J from 435 J. How high does she rise during this interval? Neglect air resistance.

- Physics -
**drwls**, Tuesday, March 15, 2011 at 7:06am1. 190,000 = (M/2)(29^2 - 21^2)

Solve for M in kg

2. K.E. loss = P.E. gain

(425 - 235) = M g H

Solve for H, the distance she rises during that interval.

(She will rise still farther until her kinetic energy is zero.)

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