A 10.00g sample of a mixture of CH4 and C2H4react with O2 at 25C and 1 atm to produce CO2 and water. If the reaction produces 520kJ of heat what is the mass percent of CH4 in the mixture? I don't want the answer just how to o
To determine the mass percent of CH4 in the mixture, we need to use the given information about the heat produced in the reaction.
Here's how you can approach the problem:
1. Begin by writing down the balanced chemical equation for the reaction:
CH4 + C2H4 + O2 → CO2 + H2O
2. Calculate the molar mass of CH4 and C2H4. The molar mass of CH4 can be found by adding up the atomic masses of carbon and hydrogen in the molecule, while the molar mass of C2H4 can be calculated using the atomic masses of carbon and hydrogen and multiplying by 2.
3. Convert the given mass of the mixture into moles of CH4 and C2H4. This can be done by dividing the mass of each component by its respective molar mass.
4. Determine the limiting reactant. To do this, compare the number of moles of CH4 and C2H4. The reactant with the lower number of moles is the limiting reactant and will be completely consumed in the reaction.
5. Use the stoichiometry of the balanced equation to calculate the number of moles of CO2 produced. Since the balanced equation shows a 1:1 mole ratio between CH4 and CO2, the number of moles of CH4 that reacted will be equal to the number of moles of CO2 produced.
6. Finally, use the mass of CH4 and the total mass of the mixture to calculate the mass percent of CH4 in the mixture. Mass percent is calculated by dividing the mass of CH4 by the total mass of the mixture and multiplying by 100.
By following these steps, you can determine the mass percent of CH4 in the mixture without directly providing the answer.