Posted by Anique on Monday, March 14, 2011 at 11:05am.
I will associate your vectors to have endpoints
P(7,10), Q(3,12) and R(-1,4)
then vector(PQ) = (-4,2)
vector(QR) = (-4,-8)
then PQ.QR = |PQ||QR|cos(theta), where theta is the angle between them
16-16 = |PQ||QR|cos(theta)
cos(theta) = 0
theta = 90 degrees
(notice the slope of lines PQ and QR are negative reciprocals of each other, so PQ and QR are perpendicular)
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