Math
posted by Diana on .
Find the smallest possible sum of six consecutive integers such that none of the integers is prime.

First list primes:
2,3,5,7,11,13,17,19,23,29,31,37,43,47,53... until there is a difference of 8 or more between two consecutive primes. Look for the smallest sum there.
Here is a list of primes up to 199:
2 3 5 7 11 13 17 19 23 29 31 37 41 43 47 53 59 61 67 71 73 79 83 89 97 101 103 107 109 113 127 131 137 139 149 151 157 163 167 173 179 181 191 193 197 199 
Prime numbers less of 200:
2 3 5 7 11 13 17 19 23 29 31 37 41 43 47 53 59 61 67 71 73 79 83 89 97 101 103 107 109 113 127 131 137 139 149 151 157 163 167 173 179 181 191 193 197 199
You must find where is difference between two prime numbers greater og 6.
First two prime nubers of difference greater og 6 is 89 and 97
So yours six consecutive integers such that none of the integers is prime:
90,91,92,93,94,95
90+91+92+93+94+95=555