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math

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(Px – 20) (100 – 2 Px + Pyg)

Differentiating with respect to P we get

100 – 4Px + Pyg + 40 = 0

I don't understand how this is calc... whenever I multiply through and take the deriv I get another answer. Do you first multiply Px through then 20??

  • math - ,

    Pyg will be treated as a constant.

    It doesn'matter how you multiply it out.

    Px*100-2Px^2+PxPyg-2000+40Px+20Pyg=f

    100-4Px+Pyg+40=0

  • math - ,

    How do the 2000 and 20pyg cancel out...the first pyg is still there?

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