Posted by **Aj** on Monday, March 14, 2011 at 1:17am.

A player uses a hockey stick to increase the speed of a 0.200 kg hockey puck by 6 m/s in 2 seconds. How much did the hockey puck accelerate? How much force was exerted on the puck? How much force did the puck exert on the hockey stick?

- Physical science -
**Don**, Monday, March 14, 2011 at 1:32am
Assuming the puck was stationary to begin with and experiences constant acceleration, vf=vi+a*t

rearrange to isolate for a, you get

a=(vf-vi)/t

but the initial velocity was zero, so

a=vf/t

once you know a,

F=m*a

Newton's Third says for every action there is a reaction, so whatever force the stick exerts on the puck, the force exerted on the stick by the puck is of equal magnitude

- Physical science -
**mary**, Saturday, March 23, 2013 at 5:49pm
what are your name

- Physics -
**Dan**, Saturday, January 9, 2016 at 11:36pm
The puck accelerated 6m/s in 2s, which (assuming constant acceleration) is 3m/s^2

f = m*a

f = 0.200kg * 3m/s^2 = 0.6N

From Newton's Third Law,

there was 0.6N exerted both on the puck by the stick, and 0.6N on the stick by the puck

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