A player uses a hockey stick to increase the speed of a 0.200 kg hockey puck by 6 m/s in 2 seconds. How much did the hockey puck accelerate? How much force was exerted on the puck? How much force did the puck exert on the hockey stick?

Assuming the puck was stationary to begin with and experiences constant acceleration, vf=vi+a*t

rearrange to isolate for a, you get
a=(vf-vi)/t
but the initial velocity was zero, so
a=vf/t

once you know a,
F=m*a

Newton's Third says for every action there is a reaction, so whatever force the stick exerts on the puck, the force exerted on the stick by the puck is of equal magnitude

what are your name

The puck accelerated 6m/s in 2s, which (assuming constant acceleration) is 3m/s^2

f = m*a
f = 0.200kg * 3m/s^2 = 0.6N
From Newton's Third Law,
there was 0.6N exerted both on the puck by the stick, and 0.6N on the stick by the puck

To find the acceleration of the hockey puck, you can use the equation:

acceleration = (change in velocity) / (time)

In this case, the change in velocity is given as 6 m/s, and the time is given as 2 seconds. Plugging the values into the formula:

acceleration = 6 m/s / 2 s = 3 m/s²

Therefore, the hockey puck accelerated at a rate of 3 m/s².

To calculate the force exerted on the puck, you can use Newton's second law of motion, which states that:

force = mass x acceleration

Here, the mass of the hockey puck is given as 0.200 kg, and the acceleration is calculated as 3 m/s². Plugging the values into the formula:

force = 0.200 kg x 3 m/s² = 0.6 N

Thus, the force exerted on the puck is 0.6 Newtons.

Now, let's consider the force exerted by the puck on the hockey stick. According to Newton's third law of motion, every action has an equal and opposite reaction. Therefore, the force exerted by the puck on the hockey stick is also 0.6 Newtons.