Physical science
posted by Aj on .
A player uses a hockey stick to increase the speed of a 0.200 kg hockey puck by 6 m/s in 2 seconds. How much did the hockey puck accelerate? How much force was exerted on the puck? How much force did the puck exert on the hockey stick?

Assuming the puck was stationary to begin with and experiences constant acceleration, vf=vi+a*t
rearrange to isolate for a, you get
a=(vfvi)/t
but the initial velocity was zero, so
a=vf/t
once you know a,
F=m*a
Newton's Third says for every action there is a reaction, so whatever force the stick exerts on the puck, the force exerted on the stick by the puck is of equal magnitude 
what are your name

The puck accelerated 6m/s in 2s, which (assuming constant acceleration) is 3m/s^2
f = m*a
f = 0.200kg * 3m/s^2 = 0.6N
From Newton's Third Law,
there was 0.6N exerted both on the puck by the stick, and 0.6N on the stick by the puck