Friday

March 27, 2015

March 27, 2015

Posted by **Mehak** on Sunday, March 13, 2011 at 11:22pm.

- Calculus -
**Damon**, Monday, March 14, 2011 at 4:56amr = 1 meter

dr/dt = .02m/min

This is the same idea as your cone problem.

The rate of change of the volume is the rate of change of the surface area times the added thickness of the surface, dr/dt

In other words:

dV/dt = 4 pi r^2 dr/dt

surface area = A = 4 pi r^2

dA/dr = 8 pi r

dA/dt = 8 pi r dr/dt

- Calculus -
**Abba**, Friday, July 29, 2011 at 9:00amT=3s

**Answer this Question**

**Related Questions**

Math - Mary is blowing up a birthday balloon.After the first breath, the balloon...

calculus - for a given patient it is determined that the blood vessel may ...

Calculus 1 - A spherical snowball melts in such a way that its surface area ...

Word Problem-Calculus - A spherical balloon is being inflated in such a way that...

Calculus - A spherical snowball is melting so that its diameter is decreasing at...

calculus - You are letting the air out of a hot air balloon at a steady rate. ...

calculus - A spherical snowball is melting in such a way that its diameter is ...

Math (Calculus) - A spherical snowball is melting in such a way that its ...

calculus - A spherical snowball is placed in the sun. The snowball melts so ...

Calculus - A spherical snowball is melting in such a way that its diameter is ...