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November 29, 2014

November 29, 2014

Posted by **Mehak** on Sunday, March 13, 2011 at 11:22pm.

- Calculus -
**Damon**, Monday, March 14, 2011 at 4:56amr = 1 meter

dr/dt = .02m/min

This is the same idea as your cone problem.

The rate of change of the volume is the rate of change of the surface area times the added thickness of the surface, dr/dt

In other words:

dV/dt = 4 pi r^2 dr/dt

surface area = A = 4 pi r^2

dA/dr = 8 pi r

dA/dt = 8 pi r dr/dt

- Calculus -
**Abba**, Friday, July 29, 2011 at 9:00amT=3s

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