Posted by **chalulu** on Sunday, March 13, 2011 at 5:30pm.

A researcher at a major hospital wishes to estimate the proportion of the adult population of the U.S. that has high blood pressure. How large a sample is needed in order to be 99% confident that the sample proportion will not differ from the tgrue proportion by more than 4%?

- statistics -
**MathGuru**, Wednesday, March 16, 2011 at 8:50pm
Formula:

n = [(z-value^2 * p * q)]/E^2

...where n = sample size, z-value will be 2.58 using a z-table to represent the 99% confidence interval, p and q represent proportions, E = .04, ^2 means squared, and * means to multiply.

Note: p and q will both be .5 if no value is stated.

Plug the values into the formula and finish the calculation. Round your answer to the next highest whole number.

- statistics -
**Anonymous**, Wednesday, October 5, 2016 at 10:41pm
3e

## Answer This Question

## Related Questions

- stat - A researcher at a major clinic wishes to estimate the proportion of the ...
- statistics - Suppose that a researcher is interested in estimating the mean ...
- Elementary Statistics - 1) Construct a confidence interval of the population ...
- Statistics - A researcher wishes to estimate the proportion of adults who have ...
- Introduction to statistics - A researcher would like to estimate the population ...
- statistics - A researcher wishes to estimate with 95% confidence the proportion ...
- statistics - A researcher wishes to estimate the proportion of adults living in ...
- statistics - please help - A researcher wishes to be 95% confident that her ...
- Stat Help - A researcher wishes to be 95% confident that her estimate of the ...
- Statistics - A researcher wishes to estimate, with 95% confidence, the ...

More Related Questions