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February 1, 2015

February 1, 2015

Posted by **Mehak** on Sunday, March 13, 2011 at 4:13pm.

- Calculus -
**Reiny**, Sunday, March 13, 2011 at 4:58pmI hope you made a diagram.

Let the distance of the boat to the dock be x m

let the length of the rope be y m

given: dy/dt = -.8 m/s

find dx/dt when x = 10

you will have the right-angled triangle such that

x^2 + 1 = y^2

2x dx/dt = 2y dy/dt

dx/dt = y/x (dy/dt)

when x=10

y^2 = 101

y = √101

dx/dt = √101/10(-.8) = -.804

the distance is decreasing at a rate of .804 m/second

- Calculus -
**Mehak**, Sunday, March 13, 2011 at 7:32pmYea i did made a diagraam and thanks .

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