Posted by ike on Sunday, March 13, 2011 at 9:37am.
To quote one of our very good math and science tutors: “You will find here at Jiskha that long series of questions, posted with no evidence of effort or thought by the person posting, will not be answered. We will gladly respond to your future questions in which your thoughts are included.”
I have removed your long list of posts so that you can re-post with your thoughts or specific questions about each one.
Ke= 1/2 m v^2= Voltate*charge
solve for v.
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